5t^2-20t=160

Solution for 5t^2-20t=160 equation:

5t^2-20t=160

We move all terms to the left:

5t^2-20t-(160)=0

a = 5; b = -20; c = -160;
Δ = b2-4ac
Δ = -202-4·5·(-160)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-60}{2*5}=\frac{-40}{10}
=-4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+60}{2*5}=\frac{80}{10}
=8
$